Be careful now

Algebra Level 5

For what values of $a$ does the equation

$\sqrt{x-5} = ax+2$

have 2 real solutions?

- \frac{1}{2} < a < 0

0 < a < \frac{1}{10}

- \frac{1}{2} < a < \frac{1}{10}, a \neq 0

- \frac{1}{2} < a < \frac{1}{10}