Beauty in Symmetry
Algebra
Level
2
\[ \begin{cases} x + y + z + 18a + b = 135802458 \\ x + y + 18z + a + b = 135802458\\ 18x + y + z + a + b = 135802458\\ x + 18y + z + a + b = 135802458\\ x + y + z + a + 18b = 135802458 \end{cases} \]
Solve the system of equations above for real values of \(x\), \(y\), \(z\), \( a\), \(b \).
Enter the value of \(x\) as your answer.
by
Abhinav Raichur