Because, it's the year 2015!

Calculus Level 4

\[{\pi \div \lim_{n \to \infty} \left [ n^{4030} \left(\dfrac{\tan^{-1}(n^{2015})}{n^{2015}} - \dfrac{\tan^{-1}(n^{2015} + 1)}{n^{2015} + 1} \right) \right ] = \ ?}\]

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