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$\log _{ 2}{ (1+\sqrt{x})}=\log_{3}{x}$

${ (\frac { 1+a^{ 2 } }{ 2a } ) }^{ y }-{( \frac { 1-a^{ 2 } }{ 2a } )}^{ y }=1,$ $0<a\le1$

$\frac { x }{ y } =?$

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