# Binomially Amazing! 3

Calculus Level 4

$\large \sum _{ n=0 }^{ 1729 }{ \frac { { \left( -1 \right) }^{ n }{ 1729 \choose n }}{ 4n+2 } ={ 2 }^{ A }\frac { B! }{ C!! } }$

Find $$A+B+C$$.

Note: The double factorial is defined as

• For an even positive integer, $$n!!=n\times (n-2)\times \cdots\times 4\times 2.$$

• For an odd positive integer, $$n!!=n\times (n-2)\times \cdots\times 3\times 1.$$

• If $$n=0$$, $$0!!=1.$$

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