# Birthday special 2

Calculus Level 5

Let $$x$$ be a positive real number. Define $A =\displaystyle\sum_{k=0}^{\infty} \dfrac{x^{3k}}{(3k)!}, \quad B = \displaystyle\sum_{k=0}^{\infty} \dfrac{x^{3k+1}}{(3k+1)!}, \quad\text{and}\quad C = \displaystyle\sum_{k=0}^{\infty} \dfrac{x^{3k+2}}{(3k+2)!}.$ Given that $$A^3+B^3+C^3 + 8ABC = 2014$$ , compute $$ABC$$ .

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