Have You Tried Adding Floors?

Algebra Level 5

\[\left\lfloor \dfrac { 2x+1 }{ 3 } \right\rfloor +\left\lfloor \dfrac { 4x+5 }{ 6 } \right\rfloor =\dfrac { 3x-1 }{ 2 } \] Find the number of real values of \(x\) satisfying the above equation.

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