Black Hole Identified #3

The Escape Velocity From A Star Is Given By This Equation : \[{\text{V}}_e=\sqrt{\frac{2\text{GM}}{R}}\] Where, \[\text{V}_e=\text{Escape Velocity}\] \[\text{G}=\text{Gravitational Constant}\] \[=6.673 \times 10^{-11} \text{N}m^2kg^{-2}\] \[\text{M}=\text{Mass of The Star}\] \[\text{R}=\text{Radius of The Star}\] Now we have to determine the Escape Velocity (in km/s) from a star which has an enormous Mass of \[6 \times 10^{30} kg\] but a Radius of only\[5.00475 km\] Clue: Plug the Mass and Radius in the Equation above. Don't forget to convert from kilometer to meter and vice versa!

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