The **Escape Velocity** From A Star Is Given By This Equation : \[{\text{V}}_e=\sqrt{\frac{2\text{GM}}{R}}\]
Where,
\[\text{V}_e=\text{Escape Velocity}\]
\[\text{G}=\text{Gravitational Constant}\]
\[=6.673 \times 10^{-11} \text{N}m^2kg^{-2}\]
\[\text{M}=\text{Mass of The Star}\]
\[\text{R}=\text{Radius of The Star}\]
Now we have to determine the **Escape Velocity (in km/s)** from a star which has an *enormous* **Mass** of \[6 \times 10^{30} kg\] but a **Radius** of only\[5.00475 km\]
**Clue:** Plug the Mass and Radius in the Equation above. Don't forget to convert from *kilometer* to *meter* and vice versa!

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