# By you

Geometry Level pending

Let $$M$$ be the midpoint of side $$BC$$ of triangle $$ABC$$. Let the median $$AM$$ intersect the incircle of $$ABC$$ at $$K$$ and $$L, K$$ being nearer to $$A$$ than $$L$$, where $$AK=KL=LM$$. If the ratio of the sides of triangle $$ABC$$ are in ratio $$x:y:z$$. Find $$x+y+z$$.

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