By youGeometry Level pending
Let \(M\) be the midpoint of side \(BC\) of triangle \(ABC\). Let the median \(AM\) intersect the incircle of \(ABC\) at \(K\) and \(L, K\) being nearer to \( A\) than \(L\), where \(AK=KL=LM\). If the ratio of the sides of triangle \(ABC\) are in ratio \(x:y:z\). Find \(x+y+z\).