By you

Geometry Level pending

Let \(M\) be the midpoint of side \(BC\) of triangle \(ABC\). Let the median \(AM\) intersect the incircle of \(ABC\) at \(K\) and \(L, K\) being nearer to \( A\) than \(L\), where \(AK=KL=LM\). If the ratio of the sides of triangle \(ABC\) are in ratio \(x:y:z\). Find \(x+y+z\).

×

Problem Loading...

Note Loading...

Set Loading...