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f(f(x))=f(x)+x\large{f(f(x)) = f(x) + x}f(f(x))=f(x)+x
Let f:R→Rf : \mathbb{R} \to \mathbb{R}f:R→R be a continuous function such that the above equation is satisfied for all x∈Rx \in \mathbb{R}x∈R, and for all x>0x > 0x>0, we have f(x)>0.f(x) > 0.f(x)>0.
If f(1)=2014, f(1)=2014,f(1)=2014, find f(2015).f(2015).f(2015).
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