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x!+11!+10!7!×5!×3!=x2 \large \frac{x! + 11! + 10!}{7! \times 5! \times 3!} \hspace{3mm} = \hspace{3mm} x^27!×5!×3!x!+11!+10!=x2
Find the value of the integer xxx satisfying this equation.
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