Given that one side of a square \(ABCD\) is on the line \(y = 2x - 17\) and the other two vertices lie on the parabola \(y = x^{2}\).

Let the minimum area of this square be denoted as \(S\). Find \(\lfloor \sqrt{S} \rfloor \).

\[\] **Notation**: \( \lfloor \cdot \rfloor \) denotes the floor function.

×

Problem Loading...

Note Loading...

Set Loading...