# Calculus 2

Calculus Level pending

$\large \sum _{n=1}^\infty \dfrac 1{( 2n+1)^{1729}} = (1-2^a) \zeta (b)$

The equation above holds true for integers $$a$$ and $$b$$, find $$b-a$$.

 Notation: $$\zeta(\cdot)$$ denotes the Riemann zeta function.

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