# Calvin's Parachute

Classical Mechanics Level pending

An aeroplane was moving horizontally when a parachute bailed out of the plane at a height $$55\omega^{2}$$ (in metres) from the ground, where $$\omega$$ is the time after which the parachute is opened after bailing out. Find the decelaration so that Calvin reached the ground with zero velocity.

Take $$(g=10\text{ m/s}^{2})$$.

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