# Calvin's Parachute

**Classical Mechanics**Level pending

An aeroplane was moving horizontally when a parachute bailed out of the plane at a height \(55\omega^{2}\) (in metres) from the ground, where \(\omega\) is the time after which the parachute is opened after bailing out. Find the decelaration so that Calvin reached the ground with zero velocity.

Take \((g=10\text{ m/s}^{2})\).