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E=∫0∞x2015(1+x)2017 dx \mathscr{E} = \displaystyle \int_{0}^{\infty} \dfrac{x^{2015}}{(1+x)^{2017}} \, dx E=∫0∞(1+x)2017x2015dx
If E \mathscr{E} E can be represented in the form ab \dfrac{a}{b} ba, with a,b a, ba,b being positive coprime integers, find a+b a + b a+b.
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