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If a,bϵ(0,2)a,b\epsilon(0,2)a,bϵ(0,2) and the equation x2+52=x−2cos(ax+b)\frac{x^{2}+5}{2}=x-2cos(ax+b)2x2+5=x−2cos(ax+b) has atleast one solution then a+b=a+b=a+b=
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