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(23−1)(33−1)(43−1)⋯(10003−1)(23+1)(33+1)(43+1)⋯(10003+1)= ?\frac{(2^3-1)(3^3-1)(4^3-1)\cdots(1000^3-1)}{(2^3+1)(3^3+1)(4^3+1)\cdots(1000^3+1)}=\, ?(23+1)(33+1)(43+1)⋯(10003+1)(23−1)(33−1)(43−1)⋯(10003−1)=?
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