Can we use a3+b3a^3+b^3 or a3b3a^3-b^3 formula?

Algebra Level 4

(231)(331)(431)(100031)(23+1)(33+1)(43+1)(10003+1)=?\frac{(2^3-1)(3^3-1)(4^3-1)\cdots(1000^3-1)}{(2^3+1)(3^3+1)(4^3+1)\cdots(1000^3+1)}=\, ?

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