Can you find it?Number Theory Level pending
Find the second least positive integer \(m\) such that \(m^3\) is the sum of \(m\) squares of consecutive integers.
Details and Assumptions
The least value is \(m=47\) where the consecutive integers start from \(22\), i.e. \(47^3=(21+1)^2+(21+2)^2\ldots(21+47)^2\)