# Can you find it?

Number Theory Level pending

Find the second least positive integer $$m$$ such that $$m^3$$ is the sum of $$m$$ squares of consecutive integers.

Details and Assumptions

1. $$m>1$$

2. The least value is $$m=47$$ where the consecutive integers start from $$22$$, i.e. $$47^3=(21+1)^2+(21+2)^2\ldots(21+47)^2$$

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