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Find the angle (in degrees) of intersection of the curves
{x3−3xy2=a3yx2−y3=b.\begin{cases} \begin{aligned} x^{3}-3xy^{2}&=a \\ 3yx^{2}-y^{3}&=b. \end{aligned} \end{cases}{x3−3xy23yx2−y3=a=b.
Details and Assumptions:
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