# Can you help, Mr Wilson?

Find the remainder when $$\displaystyle \dbinom{1994}{997}$$ is divided by $$997^{3}$$.

You may use the fact that 997 is prime .

Notation: $$\binom MN$$ denotes the binomial coefficient, $$\binom MN = \frac{M!}{N!(M-N)!}$$.

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