# Do not FOIL

Calculus Level 3

$y = \sqrt{\dfrac {x}{2} + \sqrt{\dfrac {x}{2^3} + \sqrt{\dfrac {x}{2^7} + \sqrt{\dfrac {x}{2^{15}} + \sqrt{\dfrac {x}{2^{31}} + \sqrt{\dfrac {x}{2^{63}} + \ldots }}}}} }$

...use the parameter $$\dfrac {\mathrm{d}y }{\mathrm{d}x} \geq 0$$ to find $$\dfrac {\mathrm{d}y }{\mathrm{d}x}$$ at the $$x$$-value given below. (Round your answer to two decimal places).

$x =\sqrt{2\sqrt{16 \sqrt{2\sqrt{16 \sqrt{2\sqrt{16 \ldots }}}}}}$

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