A sphere of radius \(1m\) and mass \(25 Kg\) is put on another sphere of radius \(5 m\) and \(7 Kg\) which is placed on a smooth ground. Now the upper sphere is pushed very slightly from it's equilibrium position and it begins to fall.

Now when the line joining the centre of the 2 spheres makes an angle \(\theta \) with the vertical the upper sphere loses contact with lower sphere. Then find \(\theta \) in degrees to 1 decimal place.

Details and assumptions:

1)There is no friciton between the two spheres.

2)Take \(g={ 9.8\quad m/s }^{ 2 }.\)

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