A wedge of mass \(m\) and angle \(\theta\) is placed on a smooth ground. As shown in the diagram \(A\) is a point on ground. A particle also having mass \(m\) is dropped from a height \(h\) at a horizontal distance \(x\) from \(A\). It finally touches the ground at point \(B\). Find \(\sqrt { 3 } AB\) in metres.
###### Also try Solve for trajectory Again.

Details and Assumptions

\(1)\)Take \(m=5Kg\), \(h=2\sqrt { 2 }\) metre , \(x=1\) metre.

\(2)\) \(tan(\theta)=\frac { 1 }{ \sqrt { 2 } } \)

\(3)\)The collision of the ball with the wedge is elastic and the wedge is free to move

\(4)\)\(g=9.8m/{ s }^{ 2 }\)

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