A thin rod AB of mass \(m_{1}\) and of length \(l\) is placed on a smooth horizontal ground. A point sized particle of mass \(m_{2}\) having a velocity \(v\) making an angle \(\theta\) with the line perpendicular to \(AB\) collides with the rod at point \(A\).

Assuming the collision to be elastic find \(\lfloor 100 \tan(\theta) \rfloor\) such that the point sized particle again collides with the rod at point \(B\).

**Details and assumptions:**

- \(\dfrac{m_{1}}{m_{2}}=\dfrac{12}{\pi}+2\)

Also try Solve for trajectory Again

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