Charlton syndrome just got more serious. Scientists are looking at people suffering from Charlton syndrome to observe the virus. The virus seems to be multiplying in a fixed manner. The pattern of how many viruses there are each day is as follows:

Day 1, there are: (\(2^{0}\)) viruses

Day 2, there are: (\(2^{1}\) + \(2^{0}\)) + (\(2^{0}\))viruses

Day 3, there are: (\(2^{2}\) + \(2^{1}\) + \(2^{0}\)) + (\(2^{1}\) + \(2^{0}\)) + (\(2^{0}\))viruses

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Given that a person dies when 9999 or more Charlton syndrome viruses are inside him, after how many days would someone die?

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