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If 3x+1+2y+1=7,3^{x+1} + 2^{y+1} = 7,3x+1+2y+1=7, and
3x+2y−1=2,3^x + 2^{y-1} = 2,3x+2y−1=2,
find x−yx-yx−y.
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