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The rate of a reaction doubles when its temperature changes from 300 K to 310 K. What is the activation energy of such a reaction in kJ/mol?
Note: Use R=8.314 J/K⋅molR=8.314\text{ J/K}\cdot\text{mol}R=8.314 J/K⋅mol and log2=0.301.\log2=0.301.log2=0.301.
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