Christmas Streak 12/88: BASICS!

Calculus Level 3

There is a function defined via a parameter t(>0):t\,(>0):

{y=t2+1tx=t2t2.\cases{\begin{aligned} & y=t^2+\dfrac{1}{t} \\\\ & x=t-\dfrac{2}{t^2}. \end{aligned}}

Find dxdy\frac{dx}{dy} at t=1.t=1.


This problem is a part of <Christmas Streak 2017> series.

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