Two circles intersect at \(P \) and \(Q\). \(AD\) is a line drawn meeting the circles as in the given figure. Then

(A) \(\angle APB + \angle CQD = 90^\circ \).

(B) \(\angle APB + \angle CQD = 180^\circ \).

(C) \(\angle APB = \angle CQD \).

(D) \(\angle APB - \angle CQD = 90^\circ \).

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