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The picture above depicts a 17V17\text V17V battery arranged into a circuit of five resistors (RRR). In the circuit, RI=5ΩR_I = 5\OmegaRI=5Ω, RII=7ΩR_{II} = 7\OmegaRII=7Ω, RIII=4ΩR_{III} = 4\OmegaRIII=4Ω, RIV=2ΩR_{IV} = 2\OmegaRIV=2Ω, and RV=3ΩR_V = 3\OmegaRV=3Ω. Determine the current (III) of the circuit.
Give your answer to two decimal places.
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