# Circular Motion #14

According to Newton's law of universal gravitation, the force between two point masses $$m_{1}, m_{2}$$ with separation $$r$$ is given by

$F = \frac{ G m_{1} m_{2} }{ r^{2} }$

Here, $$G$$ is the universal gravitational constant and has the value $$6.674 \times 10^{−11} \text{N m}^{2} \text{ kg}^{-2}$$. Use this information to solve the following problem:

A satellite orbits Earth in a circular orbit with radius of orbit $$\approx 42,000 \text{ km}$$. Find the time taken (in hours) by the satellite to complete one revolution.

Assumptions and details

• Mass of Earth is $$6 \times 10^{ 24 } \text{ kg}$$
• Assume Earth and satellite to be point masses.
• Ignore gravitational effects due to any other celestial body, like the Sun, Moon, other planets, etc.

This problem is part of the set - Circular Motion Practice

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