In \(\triangle ABC\), \(AD\) is the perpendicular from \(A\) onto \(BC\), \(BE\) is the median and \(CF\) is the internal angle bisector of \(\angle ACB\) such that \(D\) is on \(BC\) , \(E\) on \(AC\) and \(F\) on \(AB\). Suppose that \(AD\) , \(BE\) and \(CF\) are concurrent. If \(FE = ED = 6\) unis, find

\(\large{\dfrac{R_{AEF} + R_{FBD} + R_{EDC} + R_{DEF}}{R_{ABC}}}\)

Details and assumptions : \(R_{XYZ} = \) length of the circumradius of \(\triangle XYZ\)

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