# Not that angle again

Geometry Level 4

In parallelogram $$ABCD$$, $$F$$ and $$E$$ are on $$\overline{DC}$$ and $$\overline{BC}$$ respectively, such that $$\overline{AE}$$ and $$\overline{AF}$$ are heights. Suppose that $$CE=6$$ and $$CF=3$$ and that $$\angle{EAF}=60^{\circ}$$. Then the area of $$ABCD$$ is $$a\sqrt{b}$$ where $$b$$ is not divisible by the square of any prime. Find $$a+b$$.

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