# Coincidental residue powers?

If the last 2 digits of $$\underbrace{6\times6\times 6\times \cdots \times 6}_{\text{Number of 6's } =M}$$ is 76,

must the last 2 digits of $$\underbrace{4\times4\times 4\times \cdots \times 4}_{\text{Number of 4's } =M}$$ be 76 as well?

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