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If ∑k=018(−1)k(18k)k3+9k2+26k+24=1p\displaystyle \sum_{k=0}^{18} \frac{(-1)^k {18 \choose k}}{k^3 + 9k^2 + 26k + 24} = \frac{1}{p}k=0∑18k3+9k2+26k+24(−1)k(k18)=p1 , find ppp.
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