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(4100+2150)(4100−2150)(2+22+23+⋯+2100)= ? \large \dfrac{(4^{100} + 2^{150})(4^{100}- 2^{150}) }{(2+2^2+2^3+\cdots+2^{100} )} = \, ? (2+22+23+⋯+2100)(4100+2150)(4100−2150)=?
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