Forgot password? New user? Sign up
Existing user? Log in
A common mistake made by students is to claim that
a2+b2=a2+b2. \sqrt{a^2+b^2} = \sqrt{a^2} + \sqrt{b^2} .a2+b2=a2+b2.
How many ordered triples of integers (a,b,c) (a, b, c) (a,b,c) are there, such that each of a,b,ca,b,ca,b,c are integers from 0 to 9 inclusive, and
a2+b2−a2+c2=b2−c2? \sqrt{ a^2 + b^2} - \sqrt{a^2 + c^2} = \sqrt{b^2} - \sqrt{c^2} ? a2+b2−a2+c2=b2−c2?
Problem Loading...
Note Loading...
Set Loading...