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((x)2x)3xxi2=(((x)2x)3x)4x15x\huge \sqrt[{x^i}^2]{{\left({\left(x\right)}^{2x}\right)}^{3x}} = \sqrt[\frac{1}{5x}]{{\left({\left({\left(x\right)}^{2x}\right)}^{3x}\right)}^{4x}}xi2((x)2x)3x=5x1⎝⎛((x)2x)3x⎠⎞4x
Find the real value of xxx (upto 2 decimal places) satisfying the real equation above.
Note :- Here x≠{−1,0,1}x \neq \{-1 , 0 , 1\}x={−1,0,1}. Here iii denotes −1\sqrt{-1}−1.
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