$\huge \sqrt[{x^i}^2]{{\left({\left(x\right)}^{2x}\right)}^{3x}} = \sqrt[\frac{1}{5x}]{{\left({\left({\left(x\right)}^{2x}\right)}^{3x}\right)}^{4x}}$

Find the real value of $x$ (upto 2 decimal places) satisfying the real equation above.

**Note** :- Here $x \neq \{-1 , 0 , 1\}$. Here $i$ denotes $\sqrt{-1}$.