# Complex Fractional Equation

Algebra Level 5

Given that there is only one triplet $$(x,y,z),$$ where $$x,y$$ and $$z$$ are real numbers greater than $$3,$$ which satisfies the equation

$\frac{(x+2)^2}{y+z-2}+\frac{(y+4)^2}{z+x-4}+\frac{(z+6)^2}{x+y-6}=36,$

find the value of $$x.$$

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