# .Complex Nos.

**Algebra**Level 4

Cube Roots of \(\omega =\dfrac{3z_1-1}{2z_2+3} \) are \(\omega_1,\omega_2,\omega_3\);
Also \(\text{arg}\omega_1 <\text{arg}\omega_2<\text{arg}\omega_3 \).

Then,

\[ \dfrac{\omega_{2} ^2}{\omega_1 \omega_3}\]
would be?

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