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If x=2+5ix = 2+5ix=2+5i and 2(11!9!+13!7!)+15!5!=2ab!\large 2(\frac{1}{1!9!} +\frac{1}{3!7!}) + \frac{1}{5!5!} = \frac{2^a}{b!} 2(1!9!1+3!7!1)+5!5!1=b!2a , then the value of (x3−5x2+33x−19)(x^3 -5x^2 +33x -19)(x3−5x2+33x−19) is equal to
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