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Let $x=2013$, $y=140542$, $z=-142555$. Find $\left( \frac{x-y}{z} + \frac{y-z}{x} + \frac{z-x}{y} \right) \cdot \left( \frac{x}{y-z} + \frac{y}{z-x} + \frac{z}{x-y} \right).$

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