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z=(1+cos2α)+isin2α z = (1+cos2α)+isin2αz=(1+cos2α)+isin2α, where α∈(π2,3π2)α\in \left( \frac { \pi }{ 2 } ,\frac { 3\pi }{ 2 } \right) α∈(2π,23π) then ∣z∣|z|∣z∣ is
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