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∑n=0∞sin18∘(cos18∘)n=cotβ \large \sum_{n=0}^\infty \sin18^\circ (\cos 18^\circ)^n = \cot \beta n=0∑∞sin18∘(cos18∘)n=cotβ
Find β3/2\beta^{3/2} β3/2.
Note: 0∘≤β≤90∘0^\circ \leq \beta \leq 90^\circ0∘≤β≤90∘
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