\(\lim _{ x\rightarrow \frac { \pi }{ 6 } }{ \frac { 2-\sqrt { 3 } \cos { x-sinx } }{ { \left( 6x-\pi \right) }^{ { 2 } } } } \).

Value of above limit is of form \(\frac { p }{ q } \). Then find \(p+q\).

**Details:**

P and q are co prime numbers.

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