\[\frac { { d }^{ 2 }x }{ { d }y^{ 2 } } +2\frac { dx }{ dy } +5x=\sin { \left( y \right) } \]

Above shows a differential equation. You are given that if \(y = 0\), then \(x = 1\) and \(\dfrac{dx}{dy} = 2 \). Let \(A\) denote the value of \(x\) when \(y=30\). Find \( \lfloor 1000A \rfloor \).

Take y in degrees.

×

Problem Loading...

Note Loading...

Set Loading...