# Crazy diffy!

Calculus Level 5

$\dfrac { { d }^{ 2 }x }{ { dy }^{ 2 } } =\dfrac { 1 }{ 3 } \sqrt { 1+{ \left( \dfrac { dx }{ dy } \right) }^{ 2 } }$

Consider the differential equation above. You are given that if $$y = 0$$, then $$x=3$$ and $$\dfrac{dx}{dy} = 0$$ when $$x=0$$.

Find the value of $$x$$ when $$y = 6$$.

If the value you've found is $$z$$, submit the answer as $$\lfloor z \rfloor$$.

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