# Crazy Inequalities 2 + 400 followers problem

Algebra Level 5

$\sum_{k=1}^{400} \frac{k^{3}}{x_{k}^{2}}=1$

Given the above sum, with positive real numbers $$x_1, x_2, \ldots , x_{400}$$.

If the minimum value of $$\displaystyle \sum_{k=1}^{400} x_k$$ can be expressed as $$p^{3}$$ for a positive real $$p$$, input your answer as the greatest integer less than $$400p$$.

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