If \(\sum_{n=1}^{\infty}\frac{n^5}{x^n}= \frac{1}{x} + \frac{2^5}{x^2} + \frac{3^5}{x^3} + ...= \frac{x(Ax^4+Bx^3+Cx^2+Dx+E)}{(x-1)^6};\forall x \in \mathbb{N}\) then find the value of \(A+B+C+D+E\).

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