Forgot password? New user? Sign up

Existing user? Log in

$\large \sum_{n=0}^{123456789} \dfrac{3n^2+9n+7}{(n^2+3n+2)^3}$

Given that the summation above is equal to $\dfrac AB$, where $A$ and $B$ are coprime positive integers, find $B-A$.

Problem Loading...

Note Loading...

Set Loading...